# Practice questions for time and work issues

Posted: Posted Date – 11:50 PM, Thu – 12 May 22

This follows on from the last article on Preparing for the Police Sub-Inspector Recruitment Examination. Here are some practical questions and explanations on the subject of Time and work. To improve the calculation speed, the aspirants must practice the questions of the previous tests.

**1.** Twenty women can do a job in 16 days. Sixteen men can do the same job in 15 days. What is the relationship between the capacity of a man and that of a woman?

A.3:4

B.4:3

C.5:3

D.5:9

Answer: B

**Explanation:**

(20×16) women can complete the work in 1 day.

1 working day of a woman = 1/320.

(16×15) men can finish the job in 1 day.

1 working day of a man = 1/240

So, required ratio = 1/240 : 1/320

= 4:3 (cross multiplied)

**2.** Did 1/3 of the job in 5 days. He is then assisted by B and they finish the remaining work together in 6 days. Only B can do it in ____ days

A.22

B.22.25

around 10:50 p.m.

D. 23.50

Answer: C

**Explanation:**

Work done by A in 5 days = 1/5

Work done by A in 1 day = ((1/3)/5) = 1/15

Work done by A and B in 6 days = 2/3 [since 1- 1/3 = 2/3]

Work done by A and B in 1 day = (2/3)/6

= 2/18 => ; 1/9

Work done by B in 1 day = 1/9 – 1/15

= 5-3/45; [LCM of 9,15 is 45] = 2/45

B can complete the job 45/2 in days = 22.5 days

**3.** 2 men and 3 boys can do a job in 8 days and 3 men and 2 boys in 7 days. 5 men and 4 boys will do it in ___ days.

A.1

B.2

C.3

Day 4

Answer: D

**Explanation:**

Let 1 day of work for a man = x and 1 day of work for a boy = y.

So 2x 3y= 1/8

3x 2a= 1/7

By solving, x=1/28 and y=1/56

Work done by 5 men and 4 women in 1 day = 5/28 4/56

= (10 4)/56 => ; 14/56

Time taken by 5 men and 4 women to do the work = 56/14 = 4 days

**4.** A and B can do a job in 25 days. After A worked for 20 days, B completed the remaining work in 30 days. A alone can do it in_____ days.

A.50

B.90

Around 80

D.70

Respond to

**Explanation:**

A and B can do a job in 25 days

A and B can work in one day, AB=1/25

A worked for 20 days and B completed the remaining work in 30 days

Now, total work done in 20 days by both = (1/25) × 20 = 4/5

Remaining work = 1× (4/5) = 1/5

This work was done by B alone in 10 days.

Therefore, days taken by B to complete a unit of work = 10÷(1/5) =50 days

Work done by A in 1 day = 1/25 – 1/50 = (2-1)/50=1/50

Therefore, A can complete the job in 50 days

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